CH 16

Study guide

CH 16.1 Study Guide 1

CH 16.1 · Basic Concepts of Thermochemistry

by @mingun09

This study guide covers fundamental thermochemistry concepts including definitions of temperature, heat, specific heat, and various enthalpy changes. It details exothermic and endothermic reactions, thermochemical equations, and specific enthalpy types like molar enthalpy of formation and combustion. Students should be prepared to apply formulas, interpret reaction pathways, and understand Hess's Law for calculating overall enthalpy changes. Key distinctions include exothermic versus endothermic processes and the stability of reactants versus products.

Basic Thermochemistry Definitions

This section defines fundamental concepts in thermochemistry, including heat and enthalpy.

Concept

Temperature

Measure of average kinetic energy of the particles in a sample of matter.

Concept

Heat

Energy transferred between samples of matter because of a difference in temperature.

Concept

Specific Heat (cp)

Amount of energy required to raise the temperature of 1g of substance by 1°C (J/(g*k)).

Formula

q = c_p * m * ΔT

Energy lost or gained (q) equals specific heat (cp) times mass (m) times change in temperature (ΔT).

Concept

Enthalpy Change (ΔH)

Amount of energy absorbed by a system as heat during a process at constant pressure.

Concept

Enthalpy of Reaction

Quantity of energy transferred as heat during a chemical reaction.

Concept

Exothermic Reaction

A reaction that releases heat to the surroundings.

Exothermic Reaction Pathway

This section illustrates the energy profile for an exothermic reaction.

  1. 1

    Initial State

    Reactants begin at a higher initial enthalpy.

  2. 2

    Energy Evolved

    As the reaction proceeds, energy is released as heat to the surroundings.

  3. 3

    Final State

    Products end at a lower final enthalpy.

Key Characteristics

For an exothermic reaction, the enthalpy change (ΔH) is negative, indicating a net release of energy. The products are in a lower energy state and are therefore more stable than the reactants.

Endothermic Reaction and Pathway

This section defines endothermic reactions and illustrates their energy profile.

Concept

Endothermic Reaction

A reaction that absorbs heat from the surroundings.

  1. 1

    Initial State

    Reactants begin at a lower initial enthalpy.

  2. 2

    Energy Absorbed

    As the reaction proceeds, energy is absorbed as heat from the surroundings.

  3. 3

    Final State

    Products end at a higher final enthalpy.

Endothermic ReactionExothermic Reaction
Heat FlowAbsorbs heat from surroundingsReleases heat to surroundings
ΔH SignΔH is positiveΔH is negative
StabilityReactants are stable in a low energy stateProducts are stable in a low energy state
Enthalpy ChangeFinal enthalpy > Initial enthalpyFinal enthalpy < Initial enthalpy

Thermochemical Equation

This section defines thermochemical equations and outlines rules for their use.

Concept

Thermochemical Equation

A balanced chemical equation that includes the amount of energy released or absorbed as heat (ΔH).

Examples:

- 2H2 (g) + O2 (g) → 2H2O (g), ΔH = -483.6kJ

- H2 (g) + 1/2 O2 (g) ⇒ H2O (g), ΔH = -241.8kJ

Coefficients representCoefficients do NOT represent
QuantityNumbers of moles of reactants and productsNumbers of molecules
  • Coefficients can be fractions when necessary.
  • The physical state (g, l, s, aq) of each reactant and product must be included.
  • The enthalpy change (ΔH) is directly proportional to the number of moles of substances undergoing change. (e.g., decomposing 2 mol of water needs twice the enthalpy of 1 mol).
  • The value of ΔH is usually not significantly influenced by changing temperature.

Molar Enthalpy of Formation (ΔH_f)

This section defines molar enthalpy of formation and provides examples.

Concept

Molar Enthalpy of Formation (ΔH_f)

The enthalpy change that occurs when one mole of a compound is formed from its elements in their standard state (25 Celsius degree, 1 atm).

Examples illustrating exothermic and endothermic formation reactions:

Concept

Exothermic Formation Example

C(s) + O2(g) ⇒ CO2(g)

ΔH_f = -393.5kJ (heat is released).

Concept

Endothermic Formation Example

1/2 N2(g) + 1/2 O2(g) ⇒ NO(g)

ΔH_f = +90.29kJ (heat is absorbed).

Enthalpy of Combustion (ΔH_c)

This section defines enthalpy of combustion and provides examples.

Concept

Enthalpy of Combustion (ΔH_c)

Enthalpy change that occurs during the combustion of one mole of a substance in the presence of oxygen.

Examples of combustion reactions:

- CO (g) + 1/2 O2(g) → CO2(g), ΔH_c = -283.0kJ

- C4H10 (g) + 13/2 O2(g) ⇒ 4CO2(g) + 5H2O(l), ΔH_c = -2877.6kJ

Hess's Law and Calculations

This section introduces Hess's Law and demonstrates its application in calculations.

Concept

Hess's Law

The overall enthalpy change in a reaction is equal to the sum of the enthalpy changes for the individual steps in the process, regardless of the pathway taken.

Calculating Enthalpy of Formation for Methane Gas (CH₄)

  1. 1

    Target Reaction

    C(s) + 2H2(g) → CH₄(g) ΔH = ?

  2. 2

    Given Reactions

    1. C(s) + O2(g) → CO2(g) ΔH = −393.5 kJ

    2. H2(g) + 1/2 O2(g) → H2O(l) ΔH = −285.8 kJ

    3. CH₄(g) + 2O2(g) → CO2(g) + 2H2O(l) ΔH = −890.8 kJ

  3. 3

    Step 1: Manipulate Reaction 1

    Keep as is to get C(s) on the reactant side:

    C(s) + O2(g) ⇒ CO2(g) ΔH = -393.5kJ

  4. 4

    Step 2: Manipulate Reaction 2

    Multiply by 2 to get 2H2(g) on the reactant side and 2H2O(l) on the product side:

    2H2(g) + O2(g) → 2H2O(l) ΔH = *2 (-285.8 kJ) = -571.6kJ**

  5. 5

    Step 3: Manipulate Reaction 3

    Reverse the reaction to get CH₄(g) on the product side. This changes the sign of ΔH:

    CO2(g) + 2H2O(l) ⇒ CH4(g) + 2O2(g) ΔH = +890.8kJ

  6. 6

    Step 4: Sum the Manipulated Reactions

    Add the modified reactions and their ΔH values, canceling common species on opposite sides:

    C(s) + O2(g) + 2H2(g) + O2(g) + CO2(g) + 2H2O(l) ⇒ CO2(g) + 2H2O(l) + CH4(g) + 2O2(g)

    After canceling: C(s) + 2H2(g) ⇒ CH4(g)

Answer

ΔH = (-393.5 kJ) + (-571.6 kJ) + (+890.8 kJ) = -74.3 kJ

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